2y^2+16y=40

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Solution for 2y^2+16y=40 equation:


Simplifying
2y2 + 16y = 40

Reorder the terms:
16y + 2y2 = 40

Solving
16y + 2y2 = 40

Solving for variable 'y'.

Reorder the terms:
-40 + 16y + 2y2 = 40 + -40

Combine like terms: 40 + -40 = 0
-40 + 16y + 2y2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(-20 + 8y + y2) = 0

Factor a trinomial.
2((-10 + -1y)(2 + -1y)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(-10 + -1y)' equal to zero and attempt to solve: Simplifying -10 + -1y = 0 Solving -10 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '10' to each side of the equation. -10 + 10 + -1y = 0 + 10 Combine like terms: -10 + 10 = 0 0 + -1y = 0 + 10 -1y = 0 + 10 Combine like terms: 0 + 10 = 10 -1y = 10 Divide each side by '-1'. y = -10 Simplifying y = -10

Subproblem 2

Set the factor '(2 + -1y)' equal to zero and attempt to solve: Simplifying 2 + -1y = 0 Solving 2 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1y = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1y = 0 + -2 -1y = 0 + -2 Combine like terms: 0 + -2 = -2 -1y = -2 Divide each side by '-1'. y = 2 Simplifying y = 2

Solution

y = {-10, 2}

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